5u^2-52u+20=0

Solution for 5u^2-52u+20=0 equation:

Simplifying
5u2 + -52u + 20 = 0

Reorder the terms:
20 + -52u + 5u2 = 0

Solving
20 + -52u + 5u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(2 + -5u)(10 + -1u) = 0

Subproblem 1
Set the factor '(2 + -5u)' equal to zero and attempt to solve:

Simplifying
2 + -5u = 0

Solving
2 + -5u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -5u = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5u = 0 + -2
-5u = 0 + -2

Combine like terms: 0 + -2 = -2
-5u = -2

Divide each side by '-5'.
u = 0.4

Simplifying
u = 0.4
Subproblem 2
Set the factor '(10 + -1u)' equal to zero and attempt to solve:

Simplifying
10 + -1u = 0

Solving
10 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1u = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1u = 0 + -10
-1u = 0 + -10

Combine like terms: 0 + -10 = -10
-1u = -10

Divide each side by '-1'.
u = 10

Simplifying
u = 10
Solution
u = {0.4, 10}